Problem

Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement that allows code to be repeatedly executed.
The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

• expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

---

Task

For each integer n in the interval [a,b] (given as input) :

•  If 1<= n , then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
• Else if n > 9 and it is an even number, then print “even”.
• Else if n < 9 and it is an odd number, then print “odd”.

Input Format

The first line contains an integer, a.The second line contains an integer, b.

Constraints :-

1<=a<=b<=10^6

Output Format

Print the appropriate English representation,even, or odd, based on the conditions described in the ‘task’ section.

---

Sample Input

8
11

Sample Output

eight
nine
even
odd

---

Solution :- 

// For Loop in C - Hacker Rank Solution
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() 
{
    int a, b;
    scanf("%d\n%d", &a, &b);
   // Complete the code.
   // For Loop in C - Hacker Rank Solution START
   
    char *str[] = {"one", "two", "three", "four", "five", "six", "seven",  "eight",  "nine", "even", "odd"};

    scanf("%d\n%d", &a, &b);
    for (int i=a; i<=b; i++)// i= 8 
    {
            if (i <= 9) 
        {
                printf ("%s\n", str[i-1]);
        }
            else
        {
                printf ("%s\n", str[9+(i%2)]);
        }
        
    // For Loop in C - Hacker Rank Solution END
    
    }
    return 0;
}

Another Solution

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    int a, b;
    int n=0;
    scanf("%d\n%d", &a, &b);
  	for(n=a;n<=b;n++)
    {
    if(n==1)
    {
        printf("one\n");
    }
    if(n==2)
    {
        printf("two\n");
    }
    if(n==3)
    {
        printf("three\n");
    }
    if(n==4)
    {
        printf("four\n");
    }
    if(n==5)
    {
        printf("five\n");
    }
    if(n==6)
    {
        printf("six\n");
    }
    if(n==7)
    {
        printf("seven\n");
    }
    if(n==8)
    {
        printf("eight\n");
    }
    if(n==9)
    {
        printf("nine\n");
    }
     if(n>9)
    {
       if(n%2==0)
       {
           printf("even\n");
       }
       else {
       printf("odd\n");
       }    
    }

      }
    return 0;
}